The initial velocity of an object is u =3 i +2 j m/s. Its constant acceleration is a =5 i +3 j m/s² . The magnitude of the final velocity after 5 s is

Correct answer: C. 1073 Using the equation of motion v = u + a t Substituting the given values: v = (3 i + 2 j ) + (5 i + 3 j ) × 5 v = (3 i + 2 j ) + (25 i + 15 j ) v = 28 i + 17 j m/s The magnitude of the final velocity is: | v | = 28^2 + 17^2 | v | = 784 + 289 | v | = 1073 m/s Answer: 1073

MHT CET 202623 AprilEvening Shift

Exam: MHT CET
Year: 2026
Date: 23 April
Shift: Evening Shift
Subject: Physics
Chapter: Mathematics in Physics

MHT CET 2026 · 23 April · Evening Shift · Physics · Mathematics in Physics

The initial velocity of an object is u =3 i +2 j m/s. Its constant...

The initial velocity of an object is

\vec{u}=3\hat{i}+2\hat{j}

m/s. Its constant acceleration is

\vec{a}=5\hat{i}+3\hat{j}

m/s²

. The magnitude of the final velocity after

5 s is

Options

A $\sqrt{573}$
B $\sqrt{873}$
C $\sqrt{1073}$
D $\sqrt{373}$

Correct answer

C. $\sqrt{1073}$

Step-by-step solution

Using the equation of motion

\vec{v} = \vec{u} + \vec{a}t

Substituting the given values:

\vec{v} = (3\hat{i} + 2\hat{j}) + (5\hat{i} + 3\hat{j}) \times 5

\vec{v} = (3\hat{i} + 2\hat{j}) + (25\hat{i} + 15\hat{j})

\vec{v} = 28\hat{i} + 17\hat{j}

m/s

The magnitude of the final velocity is:

|\vec{v}| = \sqrt{28^2 + 17^2}

|\vec{v}| = \sqrt{784 + 289}

|\vec{v}| = \sqrt{1073}

m/s

Answer:

\sqrt{1073}

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