MHT CET 202622 AprilMorning Shift
- Exam
- MHT CET
- Year
- 2026
- Date
- 22 April
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Oscillations
MHT CET 2026 · 22 April · Morning Shift · Physics · Oscillations
A particle executes a linear S.H.M of amplitude 3 cm. When it is at...
A particle executes a linear S.H.M of amplitude 3 cm. When it is at 1 cm from the mean position, the magnitude of its velocity is half that of its acceleration at the point. The maximum velocity is
Options
- A cm/s
- B cm/s
- C cm/s
- D cm/s
Correct answer
D. cm/s
Step-by-step solution
Amplitude cm.
Magnitude of velocity at distance from the mean position is .
Magnitude of acceleration at distance is .
Given that at cm, .
rad/s.
Maximum velocity is v_\max = A\omega.
v_\max = 3 \times 4\sqrt{2} = 12\sqrt{2} cm/s.
Answer: cm/s
Magnitude of velocity at distance from the mean position is .
Magnitude of acceleration at distance is .
Given that at cm, .
rad/s.
Maximum velocity is v_\max = A\omega.
v_\max = 3 \times 4\sqrt{2} = 12\sqrt{2} cm/s.
Answer: cm/s