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MHT CET Medical202626 April 2026Morning ShiftPhysicsSemiconductorsActual

For an n-type semiconductor, the relation between the number density ' n_h ' and ' n_e ' is

Options

  1. An_e = n_h
  2. Bn_h << n_e
  3. Cn_h >> n_e
  4. Dn_h = n_e = 0

Correct answer

B. n_h << n_e

Step-by-step solution

In an n-type semiconductor, pentavalent impurity atoms are added to the intrinsic semiconductor. Each impurity atom donates one free electron, significantly increasing the number density of electrons. As a result, electrons become the majority charge carriers and holes become the minority charge carriers. Therefore, the number density of electrons ( n_e ) is much greater than the number density of holes ( n_h ), which can be written as n_h Answer: n_h << n_e

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