If the current gain in common-base configuration (α ) of a...

The relation between common-emitter current gain $\beta$ and common-base current gain $\alpha$ is given by $\beta = \dfrac{\alpha}{1 - \alpha}$.

For the initial state, $\alpha_1 = 0.95$.

$\beta_1 = \dfrac{0.95}{1 - 0.95} = \dfrac{0.95}{0.05} = 19$

For the final state, $\alpha_2 = 0.96$.

$\beta_2 = \dfrac{0.96}{1 - 0.96} = \dfrac{0.96}{0.04} = 24$

The change in current gain is $\Delta\beta = \beta_2 - \beta_1 = 24 - 19 = 5$.

The percentage change in $\beta$ is $\dfrac{\Delta\beta}{\beta_1} \times 100 = \dfrac{5}{19} \times 100 \approx 26.31\%$.

Thus, the percentage change is approximately $26\%$.

Answer: $26\%$