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NDA 2026
Exam
NDA
Year
2026
Subject
General Ability
Chapter
General Science

NDA 2026 · General Ability · General Science

In a certain process, the relation between pressure (P) and volume...

In a certain process, the relation between pressure (P)(P) and volume (V)(V), for an ideal gas, is given by PV2=constantPV^2 = \text{constant}. If the initial temperature is T1T_1 and the final temperature is T2T_2; and the initial volume is V1V_1 and the final volume is V2V_2, then which one of the following is correct?

Options

  1. AT1T2=V1V2\dfrac{T_1}{T_2} = \dfrac{V_1}{V_2}
  2. BT1T2=(V1V2)2\dfrac{T_1}{T_2} = \left(\dfrac{V_1}{V_2}\right)^2
  3. CT1T2=V2V1\dfrac{T_1}{T_2} = \dfrac{V_2}{V_1}
  4. DT1T2=(V2V1)2\dfrac{T_1}{T_2} = \left(\dfrac{V_2}{V_1}\right)^2

Correct answer

C. T1T2=V2V1\dfrac{T_1}{T_2} = \dfrac{V_2}{V_1}

Step-by-step solution

The given process equation is PV2=constantPV^2 = \text{constant}.

For an ideal gas, the equation of state is PV=nRTPV = nRT, which gives P=nRTVP = \dfrac{nRT}{V}.

Substituting the expression for PP into the process equation:

\left(\dfrac{nRT}{V}\right) V^2 = \text{constant}<br><br><br><br>T V = \dfrac{\text{constant}}{nR} = \text{constant}<br><br>Thisimpliesthat<br><br>This implies thatT_1 V_1 = T_2 V_2.<br><br>Rearrangingtheterms,weget:<br><br>.<br><br>Rearranging the terms, we get:<br><br>\dfrac{T_1}{T_2} = \dfrac{V_2}{V_1}<br><br>Answer:<br><br>Answer:\dfrac{T_1}{T_2} = \dfrac{V_2}{V_1}
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