Consider the following pairs of reactions and properties: Reactions Properties I. Fe(s) + 2HCl(aq) arrow FeCl_2(aq) + H_2(g) Fe is reductant II. Zn(s) + CuSO_4(aq) arrow ZnSO_4(aq) + Cu(s) Cu is being reduced III.

Question

Quantrex Academy · Accepted Answer

Correct answer: C. I, II and IV

Reaction I: Fe changes its oxidation state from 0 to +2 . It undergoes oxidation and acts as a reductant. Pair I is correct. Reaction II: Cu in CuSO_4 changes its oxidation state from +2 to 0 . It undergoes reduction. Pair II is correct. Reaction III: Br_2 changes its oxidation state from 0 to -1 . It undergoes reduction and acts as an oxidant, not a reductant. Pair III is incorrect. Reaction IV: C in CH_4 changes its oxidation state from -4 to +4 . It undergoes oxidation. Pair IV is correct. Therefore, pairs I, II, and IV are correct.

Reactions	Properties
I. $Fe(s) + 2HCl(aq) \rightarrow FeCl_2(aq) + H_2(g)$	Fe is reductant
II. $Zn(s) + CuSO_4(aq) \rightarrow ZnSO_4(aq) + Cu(s)$	Cu is being reduced
III. $Br_2(l) + 2I^-(aq) \rightarrow 2Br^-(aq) + I_2(s)$	$Br_2$ is reductant
IV. $CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l)$	C atom in $CH_4$ is oxidized

Consider the following pairs of reactions and properties: Reactions...

Options

Correct answer

Step-by-step solution

More from General Science