The energy, E , of a photon can be expressed as E = hf where f is...

$E = hf$

$[h] = \dfrac{[E]}{[f]}$

Substituting the dimensions of energy $[E] = [M L^2 T^{-2}]$ and frequency $[f] = [T^{-1}]$:

$[h] = \dfrac{[M L^2 T^{-2}]}{[T^{-1}]} = [M L^2 T^{-1}]$

Dimensions of angular momentum $L = mvr$ are $[M][L T^{-1}][L] = [M L^2 T^{-1}]$.

Therefore, the dimensions of Planck's constant are the same as that of angular momentum.

Answer: angular momentum