The energy, E , of a photon can be expressed as E = hf where f is the frequency and h is Planck's constant. The dimensions of h are the same as that of

Step-by-step solution

E = hf [h] = [E] [f] Substituting the dimensions of energy [E] = [M L^2 T⁻²] and frequency [f] = [T⁻¹] : [h] = [M L^2 T⁻²] [T⁻¹] = [M L^2 T⁻¹] Dimensions of angular momentum L = mvr are [M][L T⁻¹][L] = [M L^2 T⁻¹] . Therefore, the dimensions of Planck's constant are the same as that of angular momentum. Answer: angular momentum