The relative atomic mass of boron (which exists in two isotopic forms ¹⁰ ~B and ¹¹ ~B ) is 10.81 . What will be the abundance of ¹⁰ ~B and ¹¹ ~B , respectively (consider a sample of 100 atoms)?

Step-by-step solution

Formula used, Average atomic mass = % ~ abundance atomic mass total abundance aligned Let, % ~ of B ¹⁰ & =x % ~ of B ¹¹ & =100-x average atomic mass & =10.81 10.81 & = x 10+(100-x) 11 100 1081 & =10 x+1100-11 x -19 & =-x x & =19 % ~ of B ¹⁰ & =19 % ~ % ~ of B ¹¹ & =81 % aligned