NDA2024General AbilityGeneral ScienceActual
A uniform meter scale of mass 0.24 kg is made of steel. It is kept on two wedges, W ₁ and W ₂ , in a horizontal position. W ₁ is at a distance of 0.2 m from one of its ends, while W ₂ is at distance of 0.4 m from the other enIf the force on the scale is N ₁ due to W ₁ and N ₂ due to W ₂ , then: (take g=10.0 ~ms ⁻² )
Options
- AN ₁=1.6 ~N and N ₂=0.8 ~N
- BN ₁=0.8 ~N and N ₂=1.6 ~N
- CN ₁=0.6 ~N and N ₂=1.8 ~N
- DN ₁=1.8 ~N and N ₂=0.6 ~N
Correct answer
C. N ₁=0.6 ~N and N ₂=1.8 ~N
Step-by-step solution
As the scale is in equilibrium, net torque must be zero, aligned N ₁ d₁- N ₂ d₂ & =0 ~N ₁ 0.3 & = N ₂ 0.1 3 ~N ₁ & = N ₂ aligned Also, force must be balance, aligned N ₁+ N ₂ & = W ( mg ) N ₁+3 ~N ₂ & =0.24 10 4 ~N ₁ & =2.4 ~N ₁ & =0.6 ~N ~N ₂ & =3 ~N ₁=3 0.6=1.8 ~N aligned