A block of mass 2 kg , moving with the initial speed of 3 ~m / s comes to rest on a rough horizontal surface after travelling a distance of 3 m . The magnitude of the frictional force is:

Step-by-step solution

Given, m=2 ~kg , u=3 m s , v=0 Using, v^2-u^2=2 as array lrl & 0-9 & =2 a s & -9 & =6 a, a=-1.5 ~m / s ^2 Now, & F & =m a=2(-1.5)=-3 ~N array Negative sign indicates it is retarding force, hence magnitude of friction is 3 N .