A block of mass 2 kg , moving with the initial speed of 3 m / s comes to rest on a rough horizontal surface after travelling a distance of 3 m. The magnitude of the frictional force is:

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Correct answer: B. 3 N

Given, m=2 kg, u=3 (m)/(s), v=0 Using, v^2-u^2=2 as array lrl & 0-9 & =2 × a × s & -9 & =6 a, a=-1.5 m / s^2 Now, & F & =m a=2(-1.5)=-3 N array Negative sign indicates it is retarding force, hence magnitude of friction is 3 N .

A block of mass 2 kg , moving with the initial speed of 3 m / s...

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