Two equal resistors R are connected in parallel, and a battery of 12 V is connected across this combination. A dc current of 100 mA flows through the circuit as shown below: The value of R is

Step-by-step solution

Let R' be the equivalent resistance of two resistors. As they are connected in parallel aligned & 1 R^ = 1 R + 1 R & R^ = R 2 (i) aligned Using ohm's law V=I R^ aligned & R^ = V I = 12 100 10⁻³ & R ^ =120 aligned But, R^ = R 2 R =2 R ^ =2 120=240