If a, b, c are in AP , then what is | array lll x+1 & x+2 & x+3 x+2 & x+3 & x+4 x+a & x+b & x+3 array | equal to?

Step-by-step solution

| array lll x+1 & x+2 & x+3 x+2 & x+3 & x+4 x+a & x+b & x+3 array | Here a₃₃ element is wrong it must be x+c a, b, c are in AP 2 b=a+cC₂ C₂-C₁ and C₃ C₃-C₂ | array ccc x+1 & 1 & 1 x+2 & 1 & 1 x+a & b-a & c-b array | b-a=c-b Column C₂ and C₃ are identical. Value of determinant =0 .