NDA 2019
- Exam
- NDA
- Year
- 2019
- Subject
- Mathematics
- Chapter
- Determinants
NDA 2019 · Mathematics · Determinants
What is the value of the determinant | array lll 1! & 2! & 3! 2! &...
What is the value of the determinant
\left|\right| ?
Options
- A0
- B12
- C24
- D36
Correct answer
C. 24
Step-by-step solution
\left|\right|
Taking 2! common from and 3 ! common from C_3\Rightarrow 2!\cdot 3!\left|\right|$
On expanding, we get\begin{aligned}
& 12 \times[1(60-48)-1(40-24)+1(24-18)] \\
& =12 \times[12-16+6] \\
& =12 \times 2=24
\end{aligned}$$$