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NDA 2011
Exam
NDA
Year
2011
Subject
Mathematics
Chapter
Determinants

NDA 2011 · Mathematics · Determinants

The simultaneous equations 3 x+5 y=7 and 6 x+10 y=18 have

The simultaneous equations 3x+5y=73 x+5 y=7 and 6x+10y=186 x+10 y=18 have

Options

  1. Ano solution
  2. Binfinitely many solutions
  3. Cunique solution
  4. Dany finite number of solutions

Correct answer

A. no solution

Step-by-step solution

∵3x+5y=7\because \quad 3 x+5 y=76x+10y=1836=510≠718\begin{aligned} 6 x+10 y & =18 \\ \frac{3}{6} & =\frac{5}{10} \neq \frac{7}{18}\end{aligned}a1a2=b1b2≠c1c2\frac{a_1}{a_2}=\frac{b_1}{b_2} \neq \frac{c_1}{c_2} Equations have no solution.
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