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NDA 2025
Exam
NDA
Year
2025
Subject
Mathematics
Chapter
Functions

NDA 2025 · Mathematics · Functions

For the following two (02) items: Consider the function f(x) = 1 -...

For the following two (02) items:
Consider the function f(x)=1−(x−1)23f(x) = 1 - \sqrt[3]{(x-1)^2}.

What is the domain of the function?

Options

  1. A(1,∞)(1, \infty)
  2. B(−∞,∞)(-\infty, \infty)
  3. C(0,∞)(0, \infty)
  4. D(−∞,∞)∖{1}(-\infty, \infty) \setminus \{1\}

Correct answer

B. (−∞,∞)(-\infty, \infty)

Step-by-step solution

The given function is f(x)=1−(x−1)23f(x) = 1 - \sqrt[3]{(x-1)^2}.

The expression inside the cube root is (x−1)2(x-1)^2, which is a polynomial and is defined for all real values of xx.

Since the cube root of any real number is well-defined for all real numbers, the function f(x)f(x) is defined for all x∈Rx \in \mathbb{R}.

Therefore, the domain of the function is (−∞,∞)(-\infty, \infty).

Answer: (−∞,∞)(-\infty, \infty)
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