Consider the following for the two (02) items that follow: Let the...

Given function is $y = (1 - \cos x)^{-1} = \dfrac{1}{1 - \cos x}$

The range of $\cos x$ is $[-1, 1]$.

Since $x \neq 2n\pi$, $\cos x \neq 1$.

Therefore, $-1 \le \cos x < 1$

Multiplying by $-1$, we get $-1 < -\cos x \le 1$

Adding $1$, we get $0 < 1 - \cos x \le 2$

Taking the reciprocal, we get $\dfrac{1}{1 - \cos x} \ge \dfrac{1}{2}$

Thus, $y \ge 0.5$

The range of the function is $[0.5, \infty)$.