Consider the following for the two (02) items that follow: Let f =...

Given $f(x) = px + q$.

From the given set of points, we have $f(1) = 1$.

Substituting $x = 1$ in the function, we get:

$p(1) + q = 1$

$p + q = 1$

Alternatively, using $f(2) = 4$, we get $2p + q = 4$. Solving $p + q = 1$ and $2p + q = 4$ gives $p = 3$ and $q = -2$.

Thus, $p + q = 3 - 2 = 1$.

Answer: $1$