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NDA 2019
Exam
NDA
Year
2019
Subject
Mathematics
Chapter
Statistics

NDA 2019 · Mathematics · Statistics

The median of the observations 22,24,33,37, x+1, x+3,46 , 47,57,58...

The median of the observations 22,24,33,37,x+1,x+3,4622,24,33,37, x+1, x+3,46, 47,57,5847,57,58 in ascending order is 42. What are the values of 5 th and 6 th observations respectively?

Options

  1. A42,45
  2. B41,43
  3. C43,46
  4. D40,40

Correct answer

B. 41,43

Step-by-step solution

22,24,33,37,x+1,x+3,46,47,57,5822,24,33,37, x+1, x+3,46,47,57,58 given median =42=42(x+1)+(x+3)2=42⇒2x+42=42⇒x+2=42⇒x=40∴x+1=41x+3=43\begin{aligned} & \frac{(x+1)+(x+3)}{2}=42 \\ & \Rightarrow \frac{2 x+4}{2}=42 \\ & \Rightarrow x+2=42 \\ & \Rightarrow x=40 \\ & \therefore \quad x+1=41 \\ & x+3=43 \end{aligned}$$
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