Arithmetic mean of 10 observations is 60 and sum of squares of deviations from 50 is 5000 . What is the standard deviation of the observations?

Step-by-step solution

Given, x =60 and n=10 aligned & and ( x -50)^2=5000 & (x^2-100 x+2500 )=5000 & x^2-100 x=-20000 & x^2=60000-20000 & x^2=40,000 aligned now, aligned & = x^2 n -( x )^2 & = 4000-3600 =20 aligned