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A(1, 2, -1) , B(2, 5, -2) and C(4, 4, -3) are three vertices of a rectangle. What is the area of the rectangle?

Options

  1. A8 square units
  2. B9 square units
  3. C66 square units
  4. D68 square units

Correct answer

C. 66 square units

Step-by-step solution

The given vertices of the rectangle are A(1, 2, -1) , B(2, 5, -2) and C(4, 4, -3) . The direction ratios of the side AB are (2-1, 5-2, -2-(-1)) = (1, 3, -1) . The length of the side AB is 1^2 + 3^2 + (-1)^2 = 1 + 9 + 1 = 11 . The direction ratios of the side BC are (4-2, 4-5, -3-(-2)) = (2, -1, -1) . The length of the side BC is 2^2 + (-1)^2 + (-1)^2 = 4 + 1 + 1 = 6 . Now, checking the dot product of vectors AB and BC : AB BC = (1)(2) + (3)(-1) + (-1)(-1) = 2 - 3 + 1 = 0 Since the dot product is zero, AB is perpend

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