Passage: A line L passing through the point (-1,2,-3) is...

The plane $P$ is given by $2x + 3y + z + 5 = 0$.

The direction ratios of the normal to the plane $P$ are $\langle 2, 3, 1 \rangle$.

Since the line $M$ is parallel to the plane $P$, its direction vector must be perpendicular to the normal vector of the plane.

Let the direction ratios of the line $M$ be $\langle a, b, c \rangle$.

Then, $2a + 3b + c = 0$.

Checking the given options:

For $\langle -3, 2, 1 \rangle$, $2(-3) + 3(2) + 1 = 1 \neq 0$

For $\langle 3, 2, -6 \rangle$, $2(3) + 3(2) - 6 = 6 \neq 0$

For $\langle 1, 3, 2 \rangle$, $2(1) + 3(3) + 2 = 13 \neq 0$

For $\langle 2, 2, -10 \rangle$, $2(2) + 3(2) - 10 = 0$

Thus, the direction ratios of the line $M$ can be $\langle 2, 2, -10 \rangle$.

Answer: $\langle2,2,-10\rangle$