Identify the correct statement about ClF_3 from the following...

The central atom in $\text{ClF}_3$ is Chlorine (Cl).

Number of valence electrons of Cl = $7$.

Number of monovalent atoms (F) attached = $3$.

Steric number = $\dfrac{1}{2}(7 + 3) = 5$.

The hybridization of the central atom is $sp^3d$.

Number of bond pairs = $3$.

Number of lone pairs = $5 - 3 = 2$.

The electron geometry is trigonal bipyramidal. According to VSEPR theory, to minimize repulsion, the two lone pairs occupy the equatorial positions.

This results in a T-shaped molecular geometry.

Therefore, $\text{ClF}_3$ has a T-shaped geometry with two lone pairs on the Cl atom.

Answer: It has T-shaped geometry with two lone pairs on Cl atom.