In the structure of ClF 3 , the number of lone pairs of electrons on the central atom Cl is

Step-by-step solution

Number of hybrid orbitals = 1 2 V . E   +   M - C + A = 1 2 7 + 3 - 0 + 0 = 10 2   =   5 There are three side atoms, so, bond pair   = 3   and lone pair   =   2 ClF 3 = 3   bp + 2   lp 2 lone pair at equatorial position.