Consider the following species, CN + ,   CN - 1 ,   NO   and   CN Which one of these will have the highest bond order?

Step-by-step solution

Ion/Species Total electron Bond order NO 15 2 . 5 CN - 14 3 CN + 12 2 CN 13 2 . 5 Number of e − in NO = 7 + 8 = 15 NO = σ 1 s 2 < σ   * 1 s 2 < σ 2 s 2 < σ   * 2 s 2 < σ 2 P z 2 < π 2 P y 2 = π 2 Px 2 < π * 2 P y 1 = π   * 2 P x 0 Bond order = (number of electron in bonding molecular orbital − number of electron   in   anti   bonding   molecular