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NEET 2016
Exam
NEET
Year
2016
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

NEET 2016 · Chemistry · Chemical Bonding and Molecular Structure

Match the compounds given in column I with the hybridization and...

Match the compounds given in column I with the hybridization and shape given in column II and mark the correct option.
Column I Column II
(a) XeF6Xe{F}_{6} (i) Distorted octahedral
(b) XeO3Xe{O}_{3} (ii) Square planar
(c) XeOF4XeO{F}_{4} (iii) Pyramidal
(d) XeF4Xe{F}_{4} (iv) Square pyramidal

Options

  1. A{(a)(b)(c)(i)(iii)(iv)\begin{cases}\left(a\right) & \left(b\right) & \left(c\right) \\ \left(i\right) & \left(iii\right) & \left(iv\right)\end{cases}(d)(ii)\begin{array}{ll}\left(d\right) \\ \left(ii\right)\end{array}$$
  2. B{(a)(b)(c)(i)(ii)(iv)\begin{cases}\left(a\right) & \left(b\right) & \left(c\right) \\ \left(i\right) & \left(ii\right) & \left(iv\right)\end{cases}(d)(iii)\begin{array}{ll}\left(d\right) \\ \left(iii\right)\end{array}$$
  3. C{(a)(b)(c)(iv)(iii)(i)\begin{cases}\left(a\right) & \left(b\right) & \left(c\right) \\ \left(iv\right) & \left(iii\right) & \left(i\right)\end{cases}(d)(ii)\begin{array}{ll}\left(d\right) \\ \left(ii\right)\end{array}$$
  4. D{(a)(b)(c)(iv)(i)(ii)\begin{cases}\left(a\right) & \left(b\right) & \left(c\right) \\ \left(iv\right) & \left(i\right) & \left(ii\right)\end{cases}(d)(iii)\begin{array}{ll}\left(d\right) \\ \left(iii\right)\end{array}$$

Correct answer

A. {(a)(b)(c)(i)(iii)(iv)\begin{cases}\left(a\right) & \left(b\right) & \left(c\right) \\ \left(i\right) & \left(iii\right) & \left(iv\right)\end{cases}(d)(ii)\begin{array}{ll}\left(d\right) \\ \left(ii\right)\end{array}$$

Step-by-step solution

Molecule Hybridization Shape as per VSEPR Theory
1 XeF6Xe{F}_{6} sp3d3s{p}^{3}{d}^{3} Distored octahedron
2 XeO3Xe{O}_{3} sp3s{p}^{3} Pyramidal
3 XeOF4XeO{F}_{4} sp3d2s{p}^{3}{d}^{2} Square Pyramidal
4 XeF4Xe{F}_{4} sp3d2s{p}^{3}{d}^{2} Square planar
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