NEET2015ChemistryChemical Bonding and Molecular StructureActual
Decreasing order of stability of O 2 ,   O 2 - ,   O 2 + and O 2 2 - is:
Options
- AO 2 + > O 2 > O 2 - > O 2 2 -
- BO 2 2 - > O 2 - > O 2 > O 2 +
- CO 2 > O 2 + > O 2 2 - > O 2 -
- DO 2 - > O 2 2 - > O 2 + > O 2
Correct answer
A. O 2 + > O 2 > O 2 - > O 2 2 -
Step-by-step solution
B . O = N b   - N a 2 O 2 − ⇒ σ 1 s 2 < σ * 1 s 2 < σ 2 s 2 < σ * 2 s 2 < σ 2 p z 2 < π 2 p x 2 = π 2 p y 2 < π * 2 p x 2 = π * 2 p y 1 B.O for O 2 - = 1.5 ⇒ 10   -   7 2 = 1.5 O 2 ⇒ σ 1 s 2 < σ * 1 s 2 < σ 2 s 2 < σ * 2 s 2 < σ 2 p z 2 < π 2 p x 2 = π 2 p y 2 < π * 2 p x 1 = π * 2 p y 1 B.O for O 2 = 2.0 ⇒ 10   –   6 2