NEET2009ChemistryChemical Bonding and Molecular StructureActual
The state of hybridisation of C ₂, C ₃, C ₅ and C ₆ of the hydrocarbon, is in the following sequence
Options
- Asp , sp ^3, sp ^2 and sp ^3
- Bs p ^3, sp ^2, sp ^2 and s p
- Csp , sp ^2, sp ^2 and sp ^3
- Dsp , sp ^2, sp ^3 and sp ^2
Correct answer
A. sp , sp ^3, sp ^2 and sp ^3
Step-by-step solution
Key Idea Count number of bonds and then find hybridisation as follows. If number of bonds =2 ; hybridisation is sp , If number of bonds =3 ; hybridisation is sp ^2 , If number of bonds =4 ; hybridisation is sp ^3 . Double and triple bonds are not considered while finding hybridisation.