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NEET2006ChemistryChemical Bonding and Molecular StructureActual

The correct order regarding the electronegativity of hybrid orbitals of carbon is:

Options

  1. As p < s p^2 < s p^3
  2. Bs p>s p^2 < s p^3
  3. Cs p>s p^2>s p^3
  4. Ds p s p^3

Correct answer

C. s p>s p^2>s p^3

Step-by-step solution

In s p, s p^2 and s p^3 hybrid orbitals, the s -orbital character is 50 %, 33.3 % and 25 % , respectively, and because of the higher s -orbital character, electronegativity, increases. Related Theory The electrons of s p^3 hybridized atom are farther from the nucleus than those in s p^2 hybridized species. Therefore, s p^2 hybrid species are more stable than s p^3 hybrid species. This is because the stability is greater when the electrons are close to the nucleus.

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