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NEET 2022
Exam
NEET
Year
2022
Subject
Chemistry
Chapter
Chemical Equilibrium

NEET 2022 · Chemistry · Chemical Equilibrium

K_P for the following reaction is 3.0 at 1000 ~K . CO_2(~g)+C(s)...

KPK_P for the following reaction is 3.0 at 1000 K1000 \mathrm{~K}. CO2( g)+C(s)⇌2CO(g)\mathrm{CO}_2(\mathrm{~g})+\mathrm{C}(\mathrm{s}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}) What will be the value of KC\mathrm{K}_C for the reaction at the same temperature? (Given: R=0.083 LbarK−1 mol−1\mathrm{R}=0.083 \mathrm{~L} \mathrm{bar} \mathrm{K}^{-1} \mathrm{~mol}^{-1} )

Options

  1. A0.36
  2. B3.6×10−23.6 \times 10^{-2}
  3. C3.6×10−33.6 \times 10^{-3}
  4. D3.6

Correct answer

B. 3.6×10−23.6 \times 10^{-2}

Step-by-step solution

\begin{aligned} & \text{ } \mathrm{CO}_2(\mathrm{ g})+\mathrm{C}(\mathrm{s}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}) \\ & \mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{c}} \cdot(\mathrm{RT})^{\Delta n_{\mathrm{g}}} \\ & \mathrm{K}_{\mathrm{p}}=3.0 . \mathrm{R}=0.083 \mathrm{ L} \mathrm{bar} \mathrm{K}^{-1} \mathrm{ mol}^{-1} \\ & \begin{aligned} \Delta n_g & =2-1=1 \\ \therefore \quad 3.0 & =\mathrm{K}_{\mathrm{c}}(0.083 \times 1000)^1 \\ & \mathrm{ K}_{\mathrm{c}}=\frac{3}{83}=3.6 \times 10^{-2} \end{aligned} \end{aligned}$
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