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NEET 2015
Exam
NEET
Year
2015
Subject
Chemistry
Chapter
Chemical Equilibrium

NEET 2015 · Chemistry · Chemical Equilibrium

If the equilibrium constant for N _ 2 (g) + O _ 2 ( g ) ⇌ 2NO ( g )...

If the equilibrium constant for N2(g)+O2(g)⇌2NO(g){N}_{2}\left(g\right) + {O}_{2} ( g ) ⇌ 2NO ( g ) is K, the equilibrium constant for 12N2(g)+12O2(g)⇌NO(g)\dfrac{1}{2}{N}_{2}\left(g\right) + \dfrac{1}{2}{O}_{2} ( g ) ⇌ NO ( g ) will be:

Options

  1. AK12{K}^{\dfrac{1}{2}}
  2. B12K\dfrac{1}{2}K
  3. CKK
  4. DK2{K}^{2}

Correct answer

A. K12{K}^{\dfrac{1}{2}}

Step-by-step solution

N2(g)+O2(g)⇌2NO(g);K12 N2(g)+12O2(g)⇌NO(g);K′K=[NO2[N2][O2]K′=NO[N2]1/2[O2]1/2∴K′=K\begin{aligned} & \mathrm{N}_2(\mathrm{g})+\mathrm{O}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g}) ; \mathrm{K} \\ & \frac{1}{2} \mathrm{~N}_2(\mathrm{g})+\frac{1}{2} \mathrm{O}_2(\mathrm{g}) \rightleftharpoons \mathrm{NO}(\mathrm{g}) ; \mathrm{K}^\prime \\ & \mathrm{K}=\frac{\left[\mathrm{NO}^2\right.}{\left[\mathrm{N}_2\right]\left[\mathrm{O}_2\right]} \\ & \mathrm{K}^\prime=\frac{\mathrm{NO}}{\left[\mathrm{N}_2\right]^{1 / 2}\left[\mathrm{O}_2\right]^{1 / 2}} \\ & \therefore \mathrm{K}^\prime=\sqrt{\mathrm{K}} \end{aligned})$
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