The reaction quotient (Q) for the reaction: N_ 2(g) +3 H_ 2(g) leftharpoons 2 NH_ 3(~g) is given by Q= [ NH _3]^2 [~N_2][H_2]^3 The reaction will proceed from right to left if:

Correct answer: C. Q>K_c N_ 2(g) +3 H_ 2(g) leftharpoons 2 NH_ 3(g) aligned & K_ C = [NH_3]^2 [~N_2][H_2]^3 : & Δ n=2-4=-2 aligned Thus, the reaction moves in forward direction, when Q > K_c .

NEET 2003

Exam: NEET
Year: 2003
Subject: Chemistry
Chapter: Chemical Equilibrium

NEET 2003 · Chemistry · Chemical Equilibrium

The reaction quotient (Q) for the reaction: N_ 2(g) +3 H_ 2(g)...

The reaction quotient

(\mathrm{Q})

for the reaction:

\mathrm{N}_{2(g)}+3 \mathrm{H}_{2(g)} \rightleftharpoons 2 \mathrm{NH}_{3(\mathrm{~g})}

is given by

\mathrm{Q}=\frac{\left[\mathrm{\text{ NH }}_3\right]^2}

{

\left[\mathrm{~N}_2\right]\left[\mathrm{H}_2\right]^3}

The reaction will proceed from right to left if:

Options

A $\mathrm{Q}=\mathrm{K}_e$
B $\mathrm{Q} < \mathrm{K}_c$
C $\mathrm{Q}>\mathrm{K}_c$
D $Q=0$

Correct answer

C. $\mathrm{Q}>\mathrm{K}_c$

Step-by-step solution

\mathrm{N}_{2(g)}+3 \mathrm{H}_{2(g)} \rightleftharpoons 2 \mathrm{NH}_{3(g)}

\begin{aligned} & \mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{NH}_3\right]^2}{\left[\mathrm{~N}_2\right]\left[\mathrm{H}_2\right]^3}: \\ & \Delta n=2-4=-2 \end{aligned}

Thus, the reaction moves in forward direction, when

\mathrm{Q} > \mathrm{K}_c$.

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