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NEET 2003
Exam
NEET
Year
2003
Subject
Chemistry
Chapter
Chemical Equilibrium

NEET 2003 · Chemistry · Chemical Equilibrium

The following equilibrium are given: array ll N_2+3 H_2...

The following equilibrium are given: \begin{array}{ll} \mathrm{N}_2+3 \mathrm{H}_2 \rightleftharpoons 2 \mathrm{NH}_3 & \mathrm{~K}_1 \\ \mathrm{~N}_2+\mathrm{O}_2 \rightleftharpoons 2 \mathrm{NO} & \mathrm{K}_2 \\ \mathrm{H}_2+\frac{1}{2} \mathrm{O}_2 \rightleftharpoons \mathrm{H}_2 \mathrm{O} & \mathrm{K}_3 \end{array} The equilibrium constant of the reaction 2NH3+52O2⇌2NO+3H2O2 \mathrm{NH}_3+\frac{5}{2} \mathrm{O}_2 \rightleftharpoons 2 \mathrm{NO}+3 \mathrm{H}_2 \mathrm{O} in terms of K1, K2\mathrm{K}_1, \mathrm{~K}_2 and K3\mathrm{K}_3 is:

Options

  1. AK1 K2 K3\mathrm{K}_1 \mathrm{~K}_2 \mathrm{~K}_3
  2. BK1 K2/K3\mathrm{K}_1 \mathrm{~K}_2 / \mathrm{K}_3
  3. CK1 K32/K2\mathrm{K}_1 \mathrm{~K}_3{ }^2 / \mathrm{K}_2
  4. DK2 K33/K1\mathrm{K}_2 \mathrm{~K}_3^3 / \mathrm{K}_1

Correct answer

D. K2 K33/K1\mathrm{K}_2 \mathrm{~K}_3^3 / \mathrm{K}_1

Step-by-step solution

The given equation can be obtained by adding eq. I and III and subtracting eq. II.  equilibrium constant =K2 K33 K3\text{ equilibrium constant }=\frac{\mathrm{K}_2 \mathrm{~K}_3^3}{\mathrm{~K}_3}
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