NEET 2019
- Exam
- NEET
- Year
- 2019
- Subject
- Chemistry
- Chapter
- Electrochemistry
NEET 2019 · Chemistry · Electrochemistry
Following limiting molar conductivities are given as given as...
Following limiting molar conductivities are given as given as
\begin{aligned}& \lambda_{\mathrm{m}\left(\mathrm{H}}_{2} \mathrm{SO}}_{4}\right)}^0=\mathrm{x} \mathrm{S} \mathrm{cm}{ }^2 \mathrm{~mol}^{-1}\\
& \lambda_{\mathrm{m}\left(\mathrm{K}}_{2} \mathrm{SO}}_{4}\right)}^0=\mathrm{y} \mathrm{S} \mathrm{cm}{ }^2 \mathrm{~mol}^{-1}\\
&
\end{aligned}\lambda_{\mathrm{m}\left(\mathrm{CH}_2 \mathrm{COOK}\right)}^0=\mathrm{Z} \mathrm{S} \mathrm{cm}{ }^2 \mathrm{~mol}^{-1}
Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
Key Idea According to Kohlrausch's law,
\lambda_m^0 A_x B_y=x \lambda_{(A)^{0+}}^0+y \lambda_{(B)^{x-}}
where, limiting molar conductivity of electrolyte and are the limiting molar conductivities of cation \left(A^{y+}\right), respectively.
