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For a cell involving one electron E c e l l ⊝ = 0.59   V at 298   K , the equilibrium constant for the cell reaction is: G i v e n   t h a t   2.303   R T F = 0.059   V   a t   T = 298   K  

Options

  1. A1.0 × 10 2
  2. B1.0 × 10 5
  3. C1.0 × 10 10
  4. D1.0 × 10 30

Correct answer

C. 1.0 × 10 10

Step-by-step solution

E o = 0.59   V Δ G o = - n F E o ; Since n = 1 Δ G o = - R T   l n   K - 1 × F × 0.59 = - R T × 2.303   l o g   K 0.59 = 2.303   R T F l o g   K 0.59 = 0.059   l o g   K 10 = l o g   K K = 10 10

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