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NEET 2019
Exam
NEET
Year
2019
Subject
Chemistry
Chapter
Electrochemistry

NEET 2019 · Chemistry · Electrochemistry

For a cell involving one electron E _ cell ^ ⊝ = 0.59V at 298K ,...

For a cell involving one electron Ecell⊝=0.59V{E}_{cell}^{⊝} = 0.59V at 298K298K, the equilibrium constant for the cell reaction is:
[Giventhat2.303RTF=0.059VatT=298K]\left[Giventhat\dfrac{2.303RT}{F} = 0.059VatT = 298K\right]

Options

  1. A1.0×1021.0 \times {10}^{2}
  2. B1.0×1051.0 \times {10}^{5}
  3. C1.0×10101.0 \times {10}^{10}
  4. D1.0×10301.0 \times {10}^{30}

Correct answer

C. 1.0×10101.0 \times {10}^{10}

Step-by-step solution

{E}^{o} = 0.59V<br/><br />\Delta{G}^{o} = - nF{E}^{o};Since(n=1)Since \left(n = 1\right)
ΔGo=−RTlnK\Delta{G}^{o} = - RTlnK
−1×F×0.59=−RT×2.303logK- 1 \times F \times 0.59 = - RT \times 2.303logK
0.59=2.303RTFlogK0.59 = \dfrac{2.303RT}{F}logK
0.59=0.059logK0.59 = 0.059logK
10=logK10 = logK
K=1010K = {10}^{10}
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