In Duma's method for estimation of nitrogen, 0.25 g of an organic compound gave 40 mL of nitrogen collected at 300 K temperature and 725 mm pressure. If the aqueous tension at 300 K is 25 mm, the percentage of nitrogen in the compound is:

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Correct answer: C. 16.76

( aligned & n_ N₂ = P V R T & = (725-25) 40 10⁻³ 760 0.082 300 & n_ N₂ = 28 760 24.6 & w_ N₂ = 28 28 760 24.6 ~g of N₂ & Weight of N ₂= 28 28 760 24.6 gm & % N₂= 28 28 1 660 24.6 1 0.25 100 & =16.77 % aligned )

In Duma's method for estimation of nitrogen, 0.25 g of an organic compound gave 40 mL of nitrogen collected at 300 K temperature and 725 mm pressure. If the aqueous tension at 300 K is 25 mm, the percentage of nitrogen in the compound is:

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