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NEET 2015
Exam
NEET
Year
2015
Subject
Chemistry
Chapter
General Organic Chemistry

NEET 2015 · Chemistry · General Organic Chemistry

In Duma's method for estimation of nitrogen, 0.25 g of an organic...

In Duma's method for estimation of nitrogen, 0.25 g of an organic compound gave 40 mL of nitrogen collected at 300 K temperature and 725 mm pressure. If the aqueous tension at 300 K is 25 mm, the percentage of nitrogen in the compound is:

Options

  1. A17.36
  2. B18.20
  3. C16.76
  4. D15.76

Correct answer

C. 16.76

Step-by-step solution

nN2=PVRT=(725−25)40×10−3760×0.082×300nN2=28760×24.6wN2=28×28760×24.6g of N2Weight of N2=28×28760×24.6gm%N2=28×281660×24.6×10.25×100=16.77%\begin{aligned} & n_{N_2}=\frac{P V}{R T} \\ & =\frac{(725-25) 40 \times 10^{-3}}{760 \times 0.082 \times 300} \\ & n_{N_2}=\frac{28}{760 \times 24.6} \\ & w_{N_2}=\frac{28 \times 28}{760 \times 24.6} \mathrm{ g} \text{ of } N_2 \\ & \text{Weight of } \mathrm{N}_2=\frac{28 \times 28}{760 \times 24.6} \mathrm{gm} \\ & \% N_2=\frac{28 \times 28}{\frac{1}{660 \times 24.6}} \times \frac{1}{0.25} \times 100 \\ & =16.77 \% \end{aligned})$
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