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NEET2003ChemistryHydrocarbonsActual

The compound on reaction with NaIO ₃ in the present of KMnO ₄ gives:

Options

  1. ACH ₃ COCH ₃
  2. BCH ₃ COCH ₃+ CH ₃ COOH
  3. CCH ₃ COCH ₃+ CH ₃ CHO
  4. DCH ₃ CHO + CO ₂

Correct answer

D. CH ₃ CHO + CO ₂

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