NEET2023Chemistryp Block Elements (Group 15, 16, 17 & 18)Actual
Match list-I with List-II : List - I List - II A. Coke I. Carbon atoms are sp 3 hybridised B. Diamond II. Used as dry lubricants C. Fullerene III. Used as a reducing agent D. Graphite IV. Cage like molecules Choose the correct answer from the options given below:
Options
- AA-III, B-IV, C-I, D-II
- BA-II, B-IV, C-I, D-III
- CA-IV, B-I, C-II, D-III
- DA-III, B-I, C-IV, D-II
Correct answer
D. A-III, B-I, C-IV, D-II
Step-by-step solution
Coke when reacted with moderately reactive metal oxides at high temperature it forms CO and free metal during the metallurgical process. In this way coke play the role of removal of oxygen from metal oxide and hence act as reducing agent. In diamond each carbon atom undergoes sp 3 hybridisation and linked to four other carbon atoms by using hybridised orbitals in tetrahedral fashion. Fullerenes are the only pure form of carbon because they have smooth structure without having ‘dangling’ bonds. Fullerene