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NEET2012Chemistryp Block Elements (Group 15, 16, 17 & 18)Actual

When Cl ₂ gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from

Options

  1. Azero to +1 and zero to -5
  2. Bzero to -1 and zero to +5
  3. Czero to -1 and zero to +3
  4. Dzero to +1 and zero to -3

Correct answer

B. zero to -1 and zero to +5

Step-by-step solution

When chlorine gas reacts with hot and concentrated NaOH solution, it disproportionates into chloride ( Cl ⁻ ) and chlorate ( ClO ₃⁻ ) ions. In this process, oxidation number of chlorine changes from 0 to -1 and 0 to +5 . Note In disproportionation reactions, the same element undergoes oxidation as well as reduction.

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