NEET2010Chemistryp Block Elements (Group 15, 16, 17 & 18)Actual
Oxidation states of P in H ₄ P ₂ O ₅, H ₄ P ₂ O ₆ , H ₄ P ₂ O ₇ , are respectively
Options
- A+3,+5,+4
- B+5,+3,+4
- C+5,+4,+3
- D+3,+4,+5
Correct answer
D. +3,+4,+5
Step-by-step solution
Key Idea Oxidation state of H is +1 and that of O is -2. Let the oxidation state of P in the given compounds is x . In H ₄ P ₂ O ₅ , aligned (+1) 4+2 x+(-2) 5 & =0 4+2 x-10 & =0 2 x & =6 x & =+3 aligned array l In H ₄ P ₂ O ₆, (+1) 4+2 x +(-2) 6 =0 4+2 x -12 =0 2 x =8 x =+4 array In H ₄ P ₂ O ₇ aligned (+1) 4+2 x+(-2) 7 & =0 4+2 x-14 & =0 2 x & =10 x & =+5 aligned Thus, the oxidation states of P in H ₄ P ₂ O ₅ , H ₄ P ₂ O ₆ and H ₄ P ₂ O ₇ are +3,+4 and +5 respectively.