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NEET 2003
Exam
NEET
Year
2003
Subject
Chemistry
Chapter
p Block Elements (Group 15, 16, 17 & 18)

NEET 2003 · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

The oxidation states of sulphur in the anions SO_3^2, ~S_2 O_4^ 2-...

The oxidation states of sulphur in the anions SO32, S2O42−\mathrm{SO}_3^2, \mathrm{~S}_2 \mathrm{O}_4^{2-} and S2O62−\mathrm{S}_2 \mathrm{O}_6^{2-} follow of order

Options

  1. AS2O42−<SO32−<S2O62−\mathrm{S}_2 \mathrm{O}_4^{2-} < \mathrm{SO}_3^{2-} < \mathrm{S}_2 \mathrm{O}_6{ }^{2-}
  2. BSO32−<S2O32−<S2O62−\mathrm{SO}_3^{2-} < \mathrm{S}_2 \mathrm{O}_3^{2-} < \mathrm{S}_2 \mathrm{O}_6^{2-}
  3. CS2O42−<S2O62−<SO32−\mathrm{S}_2 \mathrm{O}_4{ }^{2-} < \mathrm{S}_2 \mathrm{O}_6{ }^{2-} < \mathrm{SO}_3{ }^{2-}
  4. DS2O62−<S2O42−<SO32−\mathrm{S}_2 \mathrm{O}_6{ }^{2-} < \mathrm{S}_2 \mathrm{O}_4{ }^{2-} < \mathrm{SO}_3{ }^{2-}

Correct answer

A. S2O42−<SO32−<S2O62−\mathrm{S}_2 \mathrm{O}_4^{2-} < \mathrm{SO}_3^{2-} < \mathrm{S}_2 \mathrm{O}_6{ }^{2-}

Step-by-step solution

Oxidation state of sulphur is SO32−\mathrm{SO}_3^{2-} i 4 Oxidation state of sulphur in S2O42−\mathrm{S}_2 \mathrm{O}_4^{2-} is 3 Oxidation state of sulphur in S2O62−\mathrm{S}_2 \mathrm{O}_6^{2-} is 5 The correct order of oxidation state is as follows: S2O\mathrm{S}_{2} \mathrm{O}}_{4}{ }^{2-} < SO32−<S\mathrm{SO}_{3}{ }^{2-} < \mathrm{S}}_{2} O62−\mathrm{O}_{6}{ }^{2-}
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