NEET2003Chemistryp Block Elements (Group 15, 16, 17 & 18)Actual
The oxidation states of sulphur in the anions SO ₃^2, ~S ₂ O ₄²⁻ and S ₂ O ₆²⁻ follow of order
Options
- AS ₂ O ₄²⁻ < SO ₃²⁻ < S ₂ O ₆ ²⁻
- BSO ₃²⁻ < S ₂ O ₃²⁻ < S ₂ O ₆²⁻
- CS ₂ O ₄ ²⁻ < S ₂ O ₆ ²⁻ < SO ₃ ²⁻
- DS ₂ O ₆ ²⁻ < S ₂ O ₄ ²⁻ < SO ₃ ²⁻
Correct answer
A. S ₂ O ₄²⁻ < SO ₃²⁻ < S ₂ O ₆ ²⁻
Step-by-step solution
Oxidation state of sulphur is SO ₃²⁻ i 4 Oxidation state of sulphur in S ₂ O ₄²⁻ is 3 Oxidation state of sulphur in S ₂ O ₆²⁻ is 5 The correct order of oxidation state is as follows: S ₂ O ₄ ²⁻ < SO ₃ ²⁻ < S ₂ O ₆ ²⁻