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NEET 2018
Exam
NEET
Year
2018
Subject
Physics
Chapter
Motion in One Dimension

NEET 2018 · Physics · Motion in One Dimension

A toy car with charge q moves on a frictionless horizontal plane...

A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric field E→\overset{\to}{E}. Due to the force qE→q\overset{\to}{E}, its velocity increases from 0 to 6ms−16m{s}^{- 1} in one second duration. At that instant the direction of the field is reversed. The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between 00 to 33 seconds are respectivelyA toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric

Options

  1. A1ms−1,3.5ms−11m{s}^{- 1}, 3.5m{s}^{- 1}
  2. B1ms−1,3ms−11m{s}^{- 1}, 3m{s}^{- 1}
  3. C2ms−1,4ms−12m{s}^{- 1}, 4m{s}^{- 1}
  4. D1.5ms−1,3ms−11.5m{s}^{- 1}, 3m{s}^{- 1}

Correct answer

B. 1ms−1,3ms−11m{s}^{- 1}, 3m{s}^{- 1}

Step-by-step solution

0<t≤1s0 < t \le 1s ~velocity increases from 0\text{0} to 6 m/s\text{6 m/s}

1s≤t≤2s1s \le t \le 2s : velocity decreases from~ 6 m/s\text{6 m/s} to~0 m/s\text{0 m/s}

But car continues to move forward and then it reverses its direction at~t=2st = 2s and after 2 s\text{2 s} accelerates backward

A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric

Distance undefined

∣12×6×2∣+∣12×(−6)×1∣| \dfrac{1}{2} \times 6 \times 2 | + | \dfrac{1}{2} \times ( - 6 ) \times 1 |

=6+3= 6 + 3

=9m= 9m

Displacement = Total area under v−t\text{v} - t graph

=6−3=3m= 6 - 3 = 3m

∴∴ Average velocity =DisplacementTime=33=1m/s= \dfrac{Displacement}{Time} = \dfrac{3}{3} = 1m/s

∴∴ Average speed =TotaldistanceTime=93=3m/s= \dfrac{Totaldistance}{Time} = \dfrac{9}{3} = 3m/s

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