Velocity is given by v=4 t(1-2 t) , then find time at which velocity is maximum

Step-by-step solution

To find value of time at which velocity is maximum, taking differentiation of v with respect to time dv dt =0 Here, v=4 t(l-2 t) array lc & v =4 t -8 t ^2 & d dt (4 t -8 t ^2 )=0 & 4-16 t =0 & t = 1 4 ~s =0.25 ~s array Again taking differentiation, d ^2 v dt ^2 =-16 0 So, at t =0.25 ~s velocity is maximum.