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NEET 2017
Exam
NEET
Year
2017
Subject
Physics
Chapter
Motion in One Dimension

NEET 2017 · Physics · Motion in One Dimension

Preeti reached the metro station and found that the escalator was...

Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time t1{t}_{1}. On other days, if she remains stationary on the moving escalator, then the escalator takes her up in time t2{t}_{2}. The time taken by her to walk up on the moving escalator will be

Options

  1. At1+t22\dfrac{{t}_{1} + {t}_{2}}{2}
  2. Bt1t2t2−t1\dfrac{{t}_{1}{t}_{2}}{{t}_{2} - {t}_{1}}
  3. Ct1t2t2+t1\dfrac{{t}_{1}{t}_{2}}{{t}_{2} + {t}_{1}}
  4. Dt1−t2{t}_{1} - {t}_{2}

Correct answer

C. t1t2t2+t1\dfrac{{t}_{1}{t}_{2}}{{t}_{2} + {t}_{1}}

Step-by-step solution

Let dd be the displacement of the escalator.

Velocity of girl w.r.t. elevator =dt1=vge= \dfrac{d}{{t}_{1}} = {v}_{ge}

Velocity of elevator w.r.t ground veG=dt2{v}_{eG} = \dfrac{d}{{t}_{2}}

Then velocity of girl w.r.t ground

v→gG=v→ge+v→eG{\overset{\to}{v}}_{gG} = {\overset{\to}{v}}_{ge} + {\overset{\to}{v}}_{eG}

i.e., VgG=Vge+VeG{V}_{gG} = {V}_{ge} + {V}_{eG}

dt=dt1+dt2\dfrac{d}{t} = \dfrac{d}{{t}_{1}} + \dfrac{d}{{t}_{2}}

1t=1t1+1t2\dfrac{1}{t} = \dfrac{1}{{t}_{1}} + \dfrac{1}{{t}_{2}}

t=t1t2(t1+t2)t = \dfrac{{t}_{1}{t}_{2}}{\left({t}_{1} + {t}_{2}\right)}

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