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NEET 2017
Exam
NEET
Year
2017
Subject
Physics
Chapter
Motion in One Dimension

NEET 2017 · Physics · Motion in One Dimension

The x and y coordinates of the particle at any time are x = 5t - 2...

The xx and yy coordinates of the particle at any time are x=5t−2t2x = 5t - 2{t}^{2} and y=10ty = 10t respectively, where xx and yy are in meters and tt is in seconds. The acceleration of the particle at t=2st = 2s is

Options

  1. A0ms−20m{s}^{- 2}
  2. B5ms−25m{s}^{- 2}
  3. C−4ms−2- 4m{s}^{- 2}
  4. D−8ms−2- 8m{s}^{- 2}

Correct answer

C. −4ms−2- 4m{s}^{- 2}

Step-by-step solution

{x=5t−2t2y=10t\begin{cases}x = 5t - 2{t}^{2} & y = 10t\end{cases}

{dxdt=5−4tdydt=10\begin{cases}\dfrac{dx}{dt} = 5 - 4t & \dfrac{dy}{dt} = 10\end{cases}

The velocity of the particle in xx and yy coordinate is

{vx=5−4tvy=10\begin{cases}{v}_{x} = 5 - 4t & {v}_{y}\end{cases} = 10

dvxdt=−4\dfrac{d{v}_{x}}{dt} = - 4 dvydt=10\dfrac{d{v}_{y}}{dt} = 10

{ax=−4ay=0\begin{cases}{a}_{x} = - 4 & {a}_{y} = 0\end{cases}

Acceleration of particle at t=2st = 2s is =−4m/s2= - 4m / {s}^{2}

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