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NEET 2015
Exam
NEET
Year
2015
Subject
Physics
Chapter
Motion in One Dimension

NEET 2015 · Physics · Motion in One Dimension

A ship A is moving Westwards with a speed of 10kmh^ - 1 and a ship...

A ship A\text{A} is moving Westwards with a speed of 10kmh−110kmh^{- 1} and a ship B100 km\text{B}\text{100 km} south of A\text{A}, is moving Northwards with a speed of 10kmh−110kmh^{- 1} . The time after which the distance between them becomes shortest, is:A ship A is moving Westwards with a speed of 10kmh^ - 1 and a ship B100 km south of A , is moving Northwards with a

Options

  1. A0h0h
  2. B5h5h
  3. C52h5\sqrt{2}h
  4. D102h10\sqrt{2}h

Correct answer

B. 5h5h

Step-by-step solution

A ship A is moving Westwards with a speed of 10kmh^ - 1 and a ship B100 km south of A , is moving Northwards with a

Relative velocity of ship B is,

∣V→BA∣=102+102=102kmph\left|{\overset{\to}{V}}_{BA}\right| = \sqrt{{10}^{2} + {10}^{2}} = 10\sqrt{2}kmph

Let shortest distance between ship A & B is AO,

Distance OB=100cos45o=502kmOB = 100cos {45}^{o} = 50\sqrt{2}km

Hence time taken to reach the shortest distance,

t=502102=5hrst = \dfrac{50\sqrt{2}}{10\sqrt{2}} = 5hrs
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