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NEET2015PhysicsMotion in One DimensionActual

A particle undergoes a one-dimensional motion such that its velocity varies according to v x = β x - 2 n , where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x is given by

Options

  1. A- 2 n β 2 x - 2 n - 1
  2. B- 2 n β 2 x - 4 n - 1
  3. C- 2 n β 2 x - 2 n + 1
  4. D- 2 n β 2 x - 4 n + 1

Correct answer

B. - 2 n β 2 x - 4 n - 1

Step-by-step solution

According to the question a = v d v d x = v d d x β x​ -2 n = - 2 n β x -2 n - 1   β x - 2 n = - 2 n β 2 x - 4 n - 1

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