A man throws balls with the same speed vertically upwards one after...

A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time?

Options

Amore than $19.6 \mathrm{~m} / \mathrm{s}$
Bat least $9.8 \mathrm{~m} / \mathrm{s}$
Cany speed less than $19.6 \mathrm{~m} / \mathrm{s}$
Donly with speed $19.6 \mathrm{~m} / \mathrm{s}$

Correct answer

A. more than $19.6 \mathrm{~m} / \mathrm{s}$

Step-by-step solution

From question Interval of ball thrown

=2 \mathrm{sec}

If we want that minimum three balls remain in air then time of flight of first ball must be greater than 4 sec.

\begin{aligned} & T>4 \mathrm{sec} \\ & \therefore \frac{2 u}{g}>4 \mathrm{sec} \\ & \Rightarrow \quad u>19.6 \mathrm{~m} / \mathrm{s} \end{aligned}

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