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NEET 2015
Exam
NEET
Year
2015
Subject
Physics
Chapter
Oscillations

NEET 2015 · Physics · Oscillations

A particle is executing a simple harmonic motion. Its maximum...

A particle is executing a simple harmonic motion. Its maximum acceleration is α\alpha and maximum velocity is β\beta. Then, its time period of vibration will be:

Options

  1. Aαβ\dfrac{\alpha}{\beta}
  2. Bβ2α\dfrac{{\beta}^{2}}{\alpha}
  3. C2πβα\dfrac{2\pi\beta}{\alpha}
  4. Dβ2α2\dfrac{{\beta}^{2}}{{\alpha}^{2}}

Correct answer

C. 2πβα\dfrac{2\pi\beta}{\alpha}

Step-by-step solution

ω2A=α{\omega}^{2}A = \alpha

\omegaA=β\omegaA = \beta

⇒ω=αβ⇒ \omega = \dfrac{\alpha}{\beta}

⇒T=2πω=2πβα⇒ T = \dfrac{2\pi}{\omega} = \dfrac{2\pi\beta}{\alpha}
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