NEET2015PhysicsOscillationsActual
A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β . Then, its time period of vibration will be:
Options
- Aα β
- Bβ 2 α
- C2 π β α
- Dβ 2 α 2
Correct answer
C. 2 π β α
Step-by-step solution
ω 2 A = α ω A = β ⇒ ω = α β ⇒ T = 2 π ω = 2 π β α