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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

NTA Abhyas 2020 · Chemistry · Carboxylic Acid Derivatives

Which of the following on treatment with hot concentrated acidified...

Which of the following on treatment with hot concentrated acidified KMnO4{KMnO}_{4} gives 2-methylhexane -1,6-dioic acid as the only organic product?Which of the following on treatment with hot concentrated acidified KMnO _ 4 gives 2-methylhexane -1,6-dioic acid asWhich of the following on treatment with hot concentrated acidified KMnO _ 4 gives 2-methylhexane -1,6-dioic acid asWhich of the following on treatment with hot concentrated acidified KMnO _ 4 gives 2-methylhexane -1,6-dioic acid asWhich of the following on treatment with hot concentrated acidified KMnO _ 4 gives 2-methylhexane -1,6-dioic acid asWhich of the following on treatment with hot concentrated acidified KMnO _ 4 gives 2-methylhexane -1,6-dioic acid as

Options

  1. ALet the foot of perpendicular from the point A(4, 3, 1) on the plane P: x - y + 2z + 3 = 0 be N . If B ( 5, α, β ) , α,
  2. BLet the foot of perpendicular from the point A(4, 3, 1) on the plane P: x - y + 2z + 3 = 0 be N . If B ( 5, α, β ) , α,
  3. CLet the foot of perpendicular from the point A(4, 3, 1) on the plane P: x - y + 2z + 3 = 0 be N . If B ( 5, α, β ) , α,
  4. DLet the foot of perpendicular from the point A(4, 3, 1) on the plane P: x - y + 2z + 3 = 0 be N . If B ( 5, α, β ) , α,

Correct answer

C. Let the foot of perpendicular from the point A(4, 3, 1) on the plane P: x - y + 2z + 3 = 0 be N . If B ( 5, α, β ) , α,

Step-by-step solution

Which of the following on treatment with hot concentrated acidified KMnO _ 4 gives 2-methylhexane -1,6-dioic acid as
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