NTA Abhyas JEE Main2020ChemistryCarboxylic Acid DerivativesPractice

CH 3 CH 2 COOH ⟶ red P Cl 2 Α ⟶ alc.KOH Β What is B ?

Options

ACH 3 CH 2 COCl
BCH 3 CH 2 CHO
CClCH 2 CH 2 COOH
DCH 2 =CHCOOH

Correct answer

D. CH 2 =CHCOOH

Step-by-step solution

1st step is Hell-Volhard Zelinsky reaction, halogenation of carboxylic acid at α - C CH 3 CH 2 COOH → red P - HCl Cl 2 CH 3 CHClCOOH → - HCl alc. KOH C H 2 = C H C O O H A c r y l i c a c i d

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