NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Chemistry
- Chapter
- Carboxylic Acid Derivatives
NTA Abhyas 2020 · Chemistry · Carboxylic Acid Derivatives
CH _ 3 CH _ 2 COOH ⟶ _ red P ^ Cl 2 Α alc.KOH ⟶ Β What is B ?
What is B ?
Options
- ACH_{3}CH_{2}COCl
- BCH_{3}CH_{2}CHO
- CClCH_{2}CH_{2}COOH
- DCH_{2}=CHCOOH
Correct answer
D. CH_{2}=CHCOOH
Step-by-step solution
1st step is Hell-Volhard Zelinsky reaction, halogenation of carboxylic acid at
\begin{cases}{CH}_{3} {CH}_{2} \text{COOH} & \mathop{→}_{\text{red P} - \text{HCl}^{\text{Cl} 2} & {CH}_{3} \text{CHClCOOH} & \mathop{→}_{- \text{HCl}^{alc. KOH} & & \end{cases}\begin{array}{ll}\text{C}{\text{H}_{2} = \text{C}\text{H}\text{C}\text{O}\text{O}\text{H} \\ \text{A}\text{c}\text{r}\text{y}\text{l}\text{i}\text{c}\text{a}\text{c}\text{i}\text{d}\end{array}$$
\begin{cases}{CH}_{3} {CH}_{2} \text{COOH} & \mathop{→}_{\text{red P} - \text{HCl}^{\text{Cl} 2} & {CH}_{3} \text{CHClCOOH} & \mathop{→}_{- \text{HCl}^{alc. KOH} & & \end{cases}\begin{array}{ll}\text{C}{\text{H}_{2} = \text{C}\text{H}\text{C}\text{O}\text{O}\text{H} \\ \text{A}\text{c}\text{r}\text{y}\text{l}\text{i}\text{c}\text{a}\text{c}\text{i}\text{d}\end{array}$$